If x +y+z = 1, xy + yz + zx = – 26 and x3 + y3+ z3 = 151, then what will be the value of xyz? यदि x +y+z = 1, xy + yz + zx = – 26 ...

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Solutions. 1. D 2. B 3. D 4. D 5. E Explanation- FOR NUMBER: Check in the following sequence only- 1. Firstly, Check the last letter: If the number of the last letter is multiple of 5 then divide it by 5. If not Check for 2, if it is multiple of 2 then it is divided by 2. 2. If the above condition dRead more

## Rohit1

Solution -: (x+y+z)² = (1)² x²+y²+z² +2(xy+yz+zx) = 1 x²+y²+z² = 1 - 2×(-26) = 53 x³+y³+z³ - 3xyz = (x+y+z)(x²+y²+z² - xy-yz-zx) 151 - 3xyz = 1×(53 +26) 3xyz = 151 - 79 = 72 xyz = 72/3 = 24